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(13x^2+5x)-2(x^2+1)=0
We multiply parentheses
-2x^2+(13x^2+5x)-2=0
We get rid of parentheses
-2x^2+13x^2+5x-2=0
We add all the numbers together, and all the variables
11x^2+5x-2=0
a = 11; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·11·(-2)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{113}}{2*11}=\frac{-5-\sqrt{113}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{113}}{2*11}=\frac{-5+\sqrt{113}}{22} $
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